// check given object's value
// return false if empty or cantain any character in "@!#%$<?>/\"
// true otherwise
// added by Tam Nguyen 04/06/2007
function checkText(item)
{
	if (item.value == "")
	{
		return false;
	}
	if (item.value.match(/[\~\!\@\#\$\^\*\;\\\/\<\>]/) != null)
	{
		return false;
	}
	
	return true;
}// end checkText()

function checkEmpty(item)
{
	if (item.value == "")
	{
		return false;
	}
	else
	{
		return true;
	}
}

function checkInvalidCharacter(item)
{
	if (item.value.match(/[\~\!\@\#\$\^\*\;\\\/\<\>]/) != null)
	{
		return false;
	}
	else
	{
		return true;
	}
}

function checkEmail (emailStr)
{

	/* The following variable tells the rest of the function whether or not
	to verify that the address ends in a two-letter country or well-known
	TLD.  1 means check it, 0 means don't. */
	
	var checkTLD=1;
	
	/* The following is the list of known TLDs that an e-mail address must end with. */
	
	var knownDomsPat=/^(com|net|org|edu|int|mil|gov|arpa|biz|aero|name|coop|info|pro|museum)$/;
	
	/* The following pattern is used to check if the entered e-mail address
	fits the user@domain format.  It also is used to separate the username
	from the domain. */
	
	var emailPat=/^(.+)@(.+)$/;
	
	/* The following string represents the pattern for matching all special
	characters.  We don't want to allow special characters in the address. 
	These characters include ( ) < > @ , ; : \ " . [ ] */
	
	var specialChars="\\(\\)><@,;:\\\\\\\"\\.\\[\\]";
	
	/* The following string represents the range of characters allowed in a 
	username or domainname.  It really states which chars aren't allowed.*/
	
	var validChars="\[^\\s" + specialChars + "\]";
	
	/* The following pattern applies if the "user" is a quoted string (in
	which case, there are no rules about which characters are allowed
	and which aren't; anything goes).  E.g. "jiminy cricket"@disney.com
	is a legal e-mail address. */
	
	var quotedUser="(\"[^\"]*\")";
	
	/* The following pattern applies for domains that are IP addresses,
	rather than symbolic names.  E.g. joe@[123.124.233.4] is a legal
	e-mail address. NOTE: The square brackets are required. */
	
	var ipDomainPat=/^\[(\d{1,3})\.(\d{1,3})\.(\d{1,3})\.(\d{1,3})\]$/;
	
	/* The following string represents an atom (basically a series of non-special characters.) */
	
	var atom=validChars + '+';
	
	/* The following string represents one word in the typical username.
	For example, in john.doe@somewhere.com, john and doe are words.
	Basically, a word is either an atom or quoted string. */
	
	var word="(" + atom + "|" + quotedUser + ")";
	
	// The following pattern describes the structure of the user
	
	var userPat=new RegExp("^" + word + "(\\." + word + ")*$");
	
	/* The following pattern describes the structure of a normal symbolic
	domain, as opposed to ipDomainPat, shown above. */
	
	var domainPat=new RegExp("^" + atom + "(\\." + atom +")*$");
	
	/* Finally, let's start trying to figure out if the supplied address is valid. */
	
	/* Begin with the coarse pattern to simply break up user@domain into
	different pieces that are easy to analyze. */
	
	var matchArray=emailStr.match(emailPat);
	
	if (matchArray==null)
	{
	
		/* Too many/few @'s or something; basically, this address doesn't
		even fit the general mould of a valid e-mail address. */
	
		//alert("Email address seems incorrect (check @ and .'s)");
		return false;
	}
	var user=matchArray[1];
	var domain=matchArray[2];
	
	// Start by checking that only basic ASCII characters are in the strings (0-127).
	
	for (i=0; i<user.length; i++)
	{
		if (user.charCodeAt(i)>127)
		{
			//alert("Ths username contains invalid characters.");
			return false;
	    }
	}
	
	for (i=0; i<domain.length; i++)
	{
		if (domain.charCodeAt(i)>127)
		{
			//alert("Ths domain name contains invalid characters.");
			return false;
		}
	}
	
	// See if "user" is valid 
	
	if (user.match(userPat)==null)
	{
	
		// user is not valid
		
		//alert("The username doesn't seem to be valid.");
		return false;
	}
	
	/* if the e-mail address is at an IP address (as opposed to a symbolic
	host name) make sure the IP address is valid. */
	
	var IPArray=domain.match(ipDomainPat);
	if (IPArray!=null)
	{
	
	// this is an IP address
	
		for (var i=1;i<=4;i++)
		{
			if (IPArray[i]>255)
			{
				//alert("Destination IP address is invalid!");
				return false;
	   		}
		}
		return true;
	}
	
	// Domain is symbolic name.  Check if it's valid.
	 
	var atomPat=new RegExp("^" + atom + "$");
	var domArr=domain.split(".");
	var len=domArr.length;
	for (i=0;i<len;i++)
	{
		if (domArr[i].search(atomPat)==-1)
		{
			//alert("The domain name does not seem to be valid.");
			return false;
	    }
	}
	
	/* domain name seems valid, but now make sure that it ends in a
	known top-level domain (like com, edu, gov) or a two-letter word,
	representing country (uk, nl), and that there's a hostname preceding 
	the domain or country. */
	
	if (checkTLD && domArr[domArr.length-1].length!=2 && domArr[domArr.length-1].search(knownDomsPat)==-1)
	{
		//alert("The address must end in a well-known domain or two letter " + "country.");
		//alert("Dia chi email phai ket thuc bang cac ten mien da co nhu .com, .net, .org, .info,.. hoac hai ky tu .dat nuoc vi du .vn, .us,.." );
		return false;
	}
	
	
	// Make sure there's a host name preceding the domain.
	
	if (len<2)
	{
		//alert("This address is missing a hostname!");
		return false;
	}
	
	// If we've gotten this far, everything's valid!
	return true;
}

function validateNumber(field) 
{ 
	if (parseInt(field.value) == field.value)
	{
		return true;
	}
	else 
	{
		return false;
	}
}
	
// return true if given item's value contain only digit and " " (space), "(" and ")"
// added by Tam Nguyen 04/06/2007
function checkPhoneNumber(item)
{
	if (item.value.match(/^[0-9 +.()]+$/) == null)
	{
		return false;
	}
	else
	{
		return true;
	}
}

// param string url
function validateUrl(url) {
	var regexp = /(ftp|http|https):\/\/(\w+:{0,1}\w*@)?(\S+)(:[0-9]+)?(\/|\/([\w#!:.?+=&%@!\-\/]))?/
	return regexp.test(url);
}

function trim(str)
{
	str = ltrim(str);
	str = rtrim(str);
	return str;
}

function ltrim(str)
{
	if (str.length == 0) return str;
	while (str.substr(0,1) == " ") 
	{
		//alert('here');
		str = str.substr(1, str.length - 1);
	}
	
	return str;
}

function rtrim(str)
{
	if (str.length == 0) return str;

	while (str.substr(str.length - 1,str.length) == " ") str = str.substr(0, str.length - 1);
	return str;
}